Morning rush
2.2 min 1,009 trips · 100% on paceOBSERVED MBTA TRAVEL TIME · 30 SERVICE DAYS
Roxbury CrossingtoStony Brook
A direct MBTA train from Roxbury Crossing to Stony Brook took a median 2.2 minutes across 5,136 observed trips; 90% of measured rides finished within approximately 2.8 minutes.
Source: MBTA Performance Data · 2026-08-20 to 2026-09-18 · Completed direct trips only
THE SHORT ANSWER
How long does Roxbury Crossing to Stony Brook take?
The median completed ride from Roxbury Crossing to Stony Brook was 2.2 minutes; the published schedule’s median was 4.2 minutes.
Based on 5,136 direct trips between 2026-08-20 and 2026-09-18, the median observed ride was 2.2 minutes. That was within 2 minutes of the published schedule.
Nine out of ten measured trips finished within approximately 2.8 minutes. These figures describe completed direct trips; they do not include the time spent waiting for the train.
WHEN YOU TRAVEL
Roxbury Crossing to Stony Brook times by daypart
Evening rush produced the fastest median for Roxbury Crossing to Stony Brook; Off-peak produced the slowest.
Differences can change as the rolling dataset updates.
Midday
2.2 min 1,082 trips · 100% on paceEvening rush
2.2 min 849 trips · 100% on paceOff-peak
2.2 min 2,196 trips · 100% on paceMEASUREMENT SAMPLE
How Roxbury Crossing to Stony Brook was measured
The Roxbury Crossing to Stony Brook estimate uses 5,136 completed direct-trip stop-timestamp pairs matched to the schedule active for each observed train.
We publish the median because one dramatic delay should not define an everyday journey, and the 90th percentile because riders still need to understand the bad end of normal.
We do not infer why a trip ran slowly. Construction, incidents, crowding and weather require separate evidence.
Read the complete method →MORE FROM Roxbury Crossing
Trips related to Roxbury Crossing to Stony Brook
The Roxbury Crossing to Stony Brook record is accompanied by 6 other measured direct rides beginning at Roxbury Crossing, each with a published median duration.